ENERGÍA LIBRE DE GIBSS
∆G°=H°-TS°
Al(OH)₃+ HNO₃ → Al (NO₃) + H₂O
∆H°=788.4J/mol 658J/mol 525.55J/mol 102.2J/mol
∆S°=570.8J/°k 234.5J°/k 385.1J/°k 165.5 J/°k
∆G°=-1.93035kj/mol-(284.150k)(-0.3927kj/°k
∆G°=-1.93035°-(-111.585705)
∆G°=-1.93035kj/mol+111.585705
∆G°=109.655355kj/mol
Al(OH)₃+ HNO₃ → Al (NO₃) + H₂O
∆H°=788.4J/mol 658J/mol 525.55J/mol 102.2J/mol
∆S°=570.8J/°k 234.5J°/k 385.1J/°k 165.5 J/°k
∆G°=-1.93035kj/mol-(284.150k)(-0.3927kj/°k
∆G°=-1.93035°-(-111.585705)
∆G°=-1.93035kj/mol+111.585705
∆G°=109.655355kj/mol
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